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Determination of The Peltier Co efficient at a Junction

A copper-iron junction is immersed in a calorimeter containing water. The Cu-Fe junction is joined to a battery, a rheostat, ammeter of a commutator. A current of i ampere, measured by an ammeter A, is passed for t second. The resulting rise in temperature of water in the calorimeter is noted. Let R be the resistance of the junction. If H1 joules are the heat produced, then

        H1 = i2 Rt + πit                                    … (1)
The same current is now passed for the same time in the reverse direction. The rise of temperature is again noted. Let H2 joules be the produced. Then,
        H2 = i2 Rt – πit                                    … (2)
From equs. (1) and (2), we have
    (H1 – H2) = 2πit
Or    π = (H1 – H2)/2it

Let M be the mass of water in the calorimeter and W the thermal capacity of the calorimeter.

Let θ1 and θ2 be the rises in temperature in the two cases respectively.
            H1 = (M + W) θ1 and H2 = (M + W) θ2
            (H1H2) =    (M + W) (θ1 – θ2)
                 Π =     (M + W) (θ1 – θ2)
Hence π is determined from the above relation.

 Determination of The Peltier

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